Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Fixed sentence to be easier to read #2251

Merged
merged 1 commit into from
Aug 27, 2024
+1 −1
Merged

Fixed sentence to be easier to read #2251

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion docs/versioned_docs/version-v111/intro.md
View file
Original file line number Diff line number Diff line change
@@ -84,7 +84,7 @@ There is no need to set the `Content-Type` or add the `DataFormat` parameter to

RestSharp will also handle both XML and JSON responses and perform all necessary deserialization tasks, depending on the server response type. Therefore, you only need to add the `Accept` header if you want to deserialize the response manually.

For example, only you'd only need these lines to make a request with JSON body:
For example, you'd only need these lines to make a request with JSON body:

```csharp
var request = new RestRequest("address/update").AddJsonBody(updatedAddress);