Remove '$' since one is automatically added when showing bash script #29790
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📝 Documentation Team Review RequiredThis pull request requires approval from the @DataDog/documentation team before it can be merged. Please ensure your changes follow our documentation guidelines and wait for a team member to review and approve your changes. |
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Hi @hush-hush, based on the build preview, this change doesn't seem to have accomplished the goal of automatically adding a $ to the commands. Did you intend to use a |
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| ```bash | ||
| chown dd-agent:dd-agent datadog-secret-backend | ||
| chmod 500 datadog-secret-backend | ||
| ``` |
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| ```bash | |
| chown dd-agent:dd-agent datadog-secret-backend | |
| chmod 500 datadog-secret-backend | |
| ``` | |
| ```sh | |
| chown dd-agent:dd-agent datadog-secret-backend | |
| chmod 500 datadog-secret-backend | |
| ``` |
| @@ -362,8 +362,8 @@ On Linux, the command outputs file mode, owner and group for the executable. On | |||
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| Example on Linux: | |||
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| ```shell | |||
| $> datadog-agent secret | |||
| ```bash | |||
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Suggested change
| ```bash | |
| ```sh |
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What does this PR do? What is the motivation?
Remove '$' since one is automatically added when showing bash script. Adding one manually produce double dollar signs.
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