added Next Greater Node in Linked List #1722

Linked_list/next-greater-node-in-linked-list/program.c

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+#include <stdio.h>
+#include <stdlib.h>
+
+struct ListNode {
+    int val;
+    struct ListNode* next;
+};
+
+// Function to create a new node
+struct ListNode* createNode(int val) {
+    struct ListNode* newNode = (struct ListNode*)malloc(sizeof(struct ListNode));
+    newNode->val = val;
+    newNode->next = NULL;
+    return newNode;
+}
+
+// Function to add a new node at the end of the list
+struct ListNode* addNode(struct ListNode* head, int val) {
+    if (head == NULL) return createNode(val);
+    struct ListNode* current = head;
+    while (current->next != NULL) {
+        current = current->next;
+    }
+    current->next = createNode(val);
+    return head;
+}
+
+// Function to convert linked list to array
+int* linkedListToArray(struct ListNode* head, int* size) {
+    int* values = (int*)malloc(10000 * sizeof(int));  // Allocate large array for simplicity
+    *size = 0;
+    while (head != NULL) {
+        values[(*size)++] = head->val;
+        head = head->next;
+    }
+    return values;
+}
+
+// Function to find the next greater node values
+int* nextLargerNodes(struct ListNode* head, int* returnSize) {
+    int size;
+    int* values = linkedListToArray(head, &size);  // Convert linked list to array
+    *returnSize = size;
+
+    int* result = (int*)calloc(size, sizeof(int));  // Initialize result array with 0
+    int* stack = (int*)malloc(size * sizeof(int));
+    int top = -1;  // Stack pointer to store indices
+
+    // Traverse the array to find the next greater element for each node
+    for (int i = 0; i < size; ++i) {
+        while (top >= 0 && values[i] > values[stack[top]]) {
+            result[stack[top]] = values[i];
+            top--;
+        }
+        stack[++top] = i;
+    }
+
+    // Clean up
+    free(values);
+    free(stack);
+    return result;
+}
+
+// Function to print the result array
+void printArray(int* array, int size) {
+    printf("Next greater nodes: ");
+    for (int i = 0; i < size; ++i) {
+        printf("%d ", array[i]);
+    }
+    printf("\n");
+}
+
+int main() {
+    struct ListNode* head = NULL;
+    head = addNode(head, 2);
+    head = addNode(head, 1);
+    head = addNode(head, 5);
+
+    int resultSize;
+    int* result = nextLargerNodes(head, &resultSize);
+
+    printArray(result, resultSize);
+
+    // Free the linked list nodes
+    while (head != NULL) {
+        struct ListNode* temp = head;
+        head = head->next;
+        free(temp);
+    }
+
+    // Free the result array
+    free(result);
+
+    return 0;
+}

Linked_list/next-greater-node-in-linked-list/readme.md

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+# Next Greater Node in Linked List
+
+## Problem Statement
+
+Given the head of a linked list with `n` nodes, find the value of the next node that is strictly greater for each node in the list. If no such node exists, return `0` for that position.
+
+Return an integer array `answer` where `answer[i]` is the value of the next greater node of the `i`th node (1-indexed). 
+
+### Example
+
+**Input:**
+head = `[2,1,5]`
+
+**Output:**
+`[5,5,0]`
+
+
+### Constraints
+- The linked list can have up to `10^4` nodes.
+- Each node contains a non-negative integer value.
+
+## Approach
+
+To solve this problem:
+1. **Convert the Linked List to an Array**: Traverse the linked list and store each node’s value in an array. This allows easy access by index.
+2. **Use a Stack to Track Indices of Nodes Waiting for a "Next Greater"**:
+   - Traverse the `values` array and maintain a stack of indices for which we haven't yet found a next greater value.
+   - For each element in `values`, check if it is greater than the elements at indices stored in the stack:
+     - If so, pop indices from the stack and set the `result` array for each index to this value.
+   - Push the current index to the stack if it doesn't have a greater element in the remainder of the array.
+3. **Return the Result Array**: After processing all elements, the `result` array contains the next greater values or `0` for nodes that have no greater value ahead.
+
+### Complexity
+- **Time Complexity**: `O(n)`, where `n` is the number of nodes, as each node is processed once.
+- **Space Complexity**: `O(n)`, for storing values in the array and using the stack.
+
+## Code Explanation
+
+### Functions
+
+1. **createNode**: Creates a new linked list node.
+2. **addNode**: Appends a node to the end of the linked list.
+3. **linkedListToArray**: Converts the linked list to an array of values.
+4. **nextLargerNodes**: The core function that computes the next greater node values.
+   - Initializes a result array `result` filled with `0`s.
+   - Uses a stack to keep track of indices where the next greater node has not been found.
+   - For each node value, checks if it’s greater than the values at indices stored in the stack. If so, it updates the result array for each index.
+5. **printArray**: Prints the result array.