sfgf.nthbday.txt

[LegacyColorValue = true]; 

{
Function    : sfgf.nthbday
Description : Find the nth business day of the month
Reference	: Calendrical Calculations, Cambridge Press, 2002

Copyright 2016 Scottfree Gains LLC

Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at

    http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
}

Inputs:
	n(Numeric),
	GYear(Numeric),
	GMonth(Numeric);

Variables:
	RDate1(0),
	ib(0),
	id(0),
	BDay(0),
	Holidays(0),
	ih(0);

Arrays:
	Holiday[20](0),
	HolidayName[20]("");	

RDate1 = sfgf.gdate2rdate(GYear, GMonth, 1);
ib = 0;
id = 0;
While ib < n Begin
	Value1 = sfgf.dayofweek(RDate1 + id);
	If Value1 >= 1 and Value1 <= 5 Then
		ib = ib + 1;
	id = id + 1;
End;
BDay = RDate1 + id - 1;
Holidays = sfgf.setholidays(GYear, True, Holiday, HolidayName);
ib = 0;
For ih = 0 To Holidays-1 Begin
	If Holiday[ih] >= RDate1 and Holiday[ih] <= BDay Then
		ib = ib + 1;
End;
sfgf.nthbday = BDay + ib;