Fibonacci Search.cpp

// C++ program of th above approach
#include <bits/stdc++.h>
using namespace std;

// Utility function to find minimum of two elements
int min(int x, int y) { return (x <= y) ? x : y; }

/* Returns index of x if present, else returns -1 */
int fibMonaccianSearch(int arr[], int x, int n)
{
	/* Initialize fibonacci numbers */
	int fibMMm2 = 0; // (m-2)'th Fibonacci No.
	int fibMMm1 = 1; // (m-1)'th Fibonacci No.
	int fibM = fibMMm2 + fibMMm1; // m'th Fibonacci

	/* fibM is going to store the smallest Fibonacci
	Number greater than or equal to n */
	while (fibM < n) {
		fibMMm2 = fibMMm1;
		fibMMm1 = fibM;
		fibM = fibMMm2 + fibMMm1;
	}

	// Marks the eliminated range from front
	int offset = -1;

	/* while there are elements to be inspected. Note that
	we compare arr[fibMm2] with x. When fibM becomes 1,
	fibMm2 becomes 0 */
	while (fibM > 1) {
		// Check if fibMm2 is a valid location
		int i = min(offset + fibMMm2, n - 1);

		/* If x is greater than the value at index fibMm2,
		cut the subarray array from offset to i */
		if (arr[i] < x) {
			fibM = fibMMm1;
			fibMMm1 = fibMMm2;
			fibMMm2 = fibM - fibMMm1;
			offset = i;
		}

		/* If x is greater than the value at index fibMm2,
		cut the subarray after i+1 */
		else if (arr[i] > x) {
			fibM = fibMMm2;
			fibMMm1 = fibMMm1 - fibMMm2;
			fibMMm2 = fibM - fibMMm1;
		}

		/* element found. return index */
		else
			return i;
	}

	/* comparing the last element with x */
	if (fibMMm1 && arr[offset + 1] == x)
		return offset + 1;

	/*element not found. return -1 */
	return -1;
}

// Driver Code
int main()
{
	int arr[]
		= { 10, 22, 35, 40, 45, 50, 80, 82, 85, 90, 100,235};
	int n = sizeof(arr) / sizeof(arr[0]);
	int x = 235;
	int ind = fibMonaccianSearch(arr, x, n);
if(ind>=0)
	cout << "Found at index: " << ind;
else
	cout << x << " isn't present in the array";

	return 0;
}

// This code is contributed by code_hunt.