Is it possible to specify the namespace prefixes and the default namespace

[couling]

I'm searching the documentation regarding namespace prefixes, but not finding anything which works. When serialising, I'm looking for a way to set the namespace prefix for specific namespaces and set the default namespace.

For example I don't want to generate this:

<ns0:foo xmlns:ns0="http://bar.example.com" />

I want to be able to specify either the default namespace:

<foo xmlns="http://bar.example.com" />

Or force the namespace to be a prefix of my chosing (bar in this example)

<bar:foo xmlns:bar="http://bar.example.com" />

---

I realise that in terms of XML standards these are all equivalent. However there are still broken interpreters around that choke on the "wrong" prefix.

[AlexandrosPlessias]

Hello @couling,

You can use below codesnap:

from xsdata.formats.dataclass.serializers.xml import XmlSerializer
from xsdata.formats.dataclass.serializers.config import SerializerConfig

serializer_config: SerializerConfig = SerializerConfig(pretty_print=True)
xml_serializer: XmlSerializer = XmlSerializer(config=serializer_config)

The foo param is the root class of your xml & ns_map can be a dict variable if you want

For
<foo xmlns="http://bar.example.com" />
try below:
xml_foo: str = xml_serializer.render(foo, ns_map={"": "http://bar.example.com"})

For
<bar:foo xmlns:bar="http://bar.example.com" />
try below:
xml_foo: str = xml_serializer.render(foo, ns_map={"": "http://bar.example.com","bar":"http://bar.example.com"})

Here you write the xml file:

with open(f"{props.OUTPUT_PATH}{export_filename}.xml", "r") as f:
     f.write(xml_foo)