How to grab the current page's URL?

[steve1316]

Description

• Pretty much the title.

async def main():
    browser = await zd.start(headless=True)
    page = await browser.get("https://www.browserscan.net/bot-detection")
    # current_url = await page.get_url()

The above is just an example but there may be use cases during web scraping where you need to peek at the page's current URL for certain information. Is there a get_url() or something equivalent for zendriver?

[steve1316]

async def main():
    browser = await zd.start(headless=True)
    page = await browser.get("https://www.browserscan.net/bot-detection")
    print(await page.evaluate("window.location.href", await_promise=True))

https://www.browserscan.net/bot-detection

I guess using evaluate for window.location.href is an option but I wonder if this harms zendriver from staying undetectable.

[Avejack]

You get the current URL by doing:

current_url = page.target.url

[stephanlensky]

@Avejack is correct, I'll mark this as completed for now.

BTW, I don't think using page.evaluate like that should harm the undetectability (but, using page.target.url is still much easier).

[Sejmou]

Should page.evaluate("window.location.href", await_promise=True) always produce the same output as page.target.url?

I encountered an instance where this wasn't the case. It happened when the browser got redirected because a verification code was requested. page.target.url still returned the previous url the browser visited while page.evaluate(...) returned the actual URL that was also displayed in the browser's address bar.