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Time: 18 ms (36.98%) | Memory: 26.2 MB (89.54%) - LeetSync
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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TreeNode *Tree(vector<int>& in, int x, int y,vector<int>& po,int a,int b){
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if(x > y || a > b)return nullptr;
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TreeNode *node = new TreeNode(po[b]);
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int SI = x;
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while(node->val != in[SI])SI++;
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node->left = Tree(in,x,SI-1,po,a,a+SI-x-1);
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node->right = Tree(in,SI+1,y,po,a+SI-x,b-1);
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return node;
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}
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TreeNode* buildTree(vector<int>& in, vector<int>& po){
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return Tree(in,0,in.size()-1,po,0,po.size()-1);
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}
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};

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