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3c) #RM = (2^10) * 11 * 5 giusto? |
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Perché nel terzo rigo del punto 3a hai scritto che per calcolare i max record per blocco del file indice dividi 50 000 per 45+4 e non 2048? sicuro sia giusto? |
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Sono un po' arrugginito sull'argomento, anche se rifacessi l'esercizio sarebbe poco attendibile la risposta 🙃 |
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250k = NR 350 = RS 45 = KS 2048 = BS 4 = PS RpB = <(BS/RS) = <(2048/350) = 5 TotBlockMain = >(NR/RpB) = >(250000/5) = 50k RpBI = <(BS/PS + KS) = <(2048/4+45) = 41 TotBlockIndex = >(TotBlockMain/RpBI) = >(50.000/41) = 1220 AccessTime = >(log_2(1220) + 1) = 12 |
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