1295. Find Numbers with Even Number of Digits.py

class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        nums = [1 for i in nums if len(str(i))%2==0] # lopp through each number in the list -> convert each num into string -> check the length if it is multiple of 2 -> append 1 in the list-> return the length of the list
        return len(nums)
        
'''
Given an array nums of integers, return how many of them contain an even number of digits.

 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.
Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.
'''