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It seems to me that As a workaround, you can perform multiplications instead for now. |
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This post by @triska brought Scryer's built-in rational number support to my attention. Because of results like this ...
... I would like to do some probability calculations exactly. This requires doing$q^n$ for $q \in \mathbb{Q}, n \in \mathbb{N}$ . But both 'obvious' operators yield a floating-point result:
Is Scryer's rational number support documented anywhere?
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