You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a triple booking.
A triple booking happens when three events have some non-empty intersection (i.e., some moment is common to all the three events.).
The event can be represented as a pair of integers start
and end
that represents a booking on the half-open interval [start, end)
, the range of real numbers x
such that start <= x < end
.
Implement the MyCalendarTwo
class:
MyCalendarTwo()
Initializes the calendar object.boolean book(int start, int end)
Returnstrue
if the event can be added to the calendar successfully without causing a triple booking. Otherwise, returnfalse
and do not add the event to the calendar.
Example 1:
Input ["MyCalendarTwo", "book", "book", "book", "book", "book", "book"] [[], [10, 20], [50, 60], [10, 40], [5, 15], [5, 10], [25, 55]] Output [null, true, true, true, false, true, true] Explanation MyCalendarTwo myCalendarTwo = new MyCalendarTwo(); myCalendarTwo.book(10, 20); // return True, The event can be booked. myCalendarTwo.book(50, 60); // return True, The event can be booked. myCalendarTwo.book(10, 40); // return True, The event can be double booked. myCalendarTwo.book(5, 15); // return False, The event ca not be booked, because it would result in a triple booking. myCalendarTwo.book(5, 10); // return True, The event can be booked, as it does not use time 10 which is already double booked. myCalendarTwo.book(25, 55); // return True, The event can be booked, as the time in [25, 40) will be double booked with the third event, the time [40, 50) will be single booked, and the time [50, 55) will be double booked with the second event.
Constraints:
0 <= start < end <= 109
- At most
1000
calls will be made tobook
.
Companies:
Google, Microsoft, Amazon
Related Topics:
Design, Segment Tree, Ordered Set
Similar Questions:
// OJ: https://leetcode.com/problems/my-calendar-ii/
// Author: github.com/lzl124631x
// Time:
// MyCalendarTwo: O(1)
// book: O(N)
// Space: O(N)
class MyCalendarTwo {
map<int, int> m; // number -> diff
public:
MyCalendarTwo() {}
bool book(int start, int end) {
m[start]++;
m[end]--;
int sum = 0;
for (auto &[n, d] : m) {
sum += d;
if (sum > 2) {
if (--m[start] == 0) m.erase(start);
if (++m[end] == 0) m.erase(end);
return false;
}
}
return true;
}
};