Description
Given three tables: salesperson, company, orders.
Output all the names in the table salesperson, who didn’t have sales to company 'RED'.
Example
Input
Table: salesperson
+----------+------+--------+-----------------+-----------+ | sales_id | name | salary | commission_rate | hire_date | +----------+------+--------+-----------------+-----------+ | 1 | John | 100000 | 6 | 4/1/2006 | | 2 | Amy | 120000 | 5 | 5/1/2010 | | 3 | Mark | 65000 | 12 | 12/25/2008| | 4 | Pam | 25000 | 25 | 1/1/2005 | | 5 | Alex | 50000 | 10 | 2/3/2007 | +----------+------+--------+-----------------+-----------+The table
salesperson holds the salesperson information. Every salesperson has a sales_id and a name.
Table: company
+---------+--------+------------+ | com_id | name | city | +---------+--------+------------+ | 1 | RED | Boston | | 2 | ORANGE | New York | | 3 | YELLOW | Boston | | 4 | GREEN | Austin | +---------+--------+------------+The table
company holds the company information. Every company has a com_id and a name.
Table: orders
+----------+----------+---------+----------+--------+ | order_id | date | com_id | sales_id | amount | +----------+----------+---------+----------+--------+ | 1 | 1/1/2014 | 3 | 4 | 100000 | | 2 | 2/1/2014 | 4 | 5 | 5000 | | 3 | 3/1/2014 | 1 | 1 | 50000 | | 4 | 4/1/2014 | 1 | 4 | 25000 | +----------+----------+---------+----------+--------+The table
orders holds the sales record information, salesperson and customer company are represented by sales_id and com_id.output
+------+ | name | +------+ | Amy | | Mark | | Alex | +------+
Explanation
According to order '3' and '4' in table orders, it is easy to tell only salesperson 'John' and 'Alex' have sales to company 'RED',
so we need to output all the other names in table salesperson.
# OJ: https://leetcode.com/problems/sales-person/
# Author: github.com/lzl124631x
SELECT
s.name
FROM
salesperson s
WHERE
s.sales_id NOT IN (
SELECT
o.sales_id
FROM
orders o
LEFT JOIN
company c ON o.com_id = c.com_id
WHERE
c.name = 'RED'
)