Given an array of integer arrays arrays where each arrays[i] is sorted in strictly increasing order, return an integer array representing the longest common subsequence between all the arrays.
A subsequence is a sequence that can be derived from another sequence by deleting some elements (possibly none) without changing the order of the remaining elements.
Example 1:
Input: arrays = [[1,3,4],
[1,4,7,9]]
Output: [1,4]
Explanation: The longest common subsequence in the two arrays is [1,4].
Example 2:
Input: arrays = [[2,3,6,8],
[1,2,3,5,6,7,10],
[2,3,4,6,9]]
Output: [2,3,6]
Explanation: The longest common subsequence in all three arrays is [2,3,6].
Example 3:
Input: arrays = [[1,2,3,4,5],
[6,7,8]]
Output: []
Explanation: There is no common subsequence between the two arrays.
Constraints:
2 <= arrays.length <= 1001 <= arrays[i].length <= 1001 <= arrays[i][j] <= 100arrays[i]is sorted in strictly increasing order.
Companies:
Google
Related Topics:
Array, Hash Table, Counting
Similar Questions:
// OJ: https://leetcode.com/problems/longest-common-subsequence-between-sorted-arrays/
// Author: github.com/lzl124631x
// Time: O(NL)
// Space: O(R) where `R` is the range of numbers in `A`
class Solution {
public:
vector<int> longestCommonSubsequence(vector<vector<int>>& A) {
int cnt[101] = {};
vector<int> ans;
for (auto &v : A) {
for (int n : v) {
if (++cnt[n] == A.size()) ans.push_back(n);
}
}
return ans;
}
};