You are given two strings word1
and word2
. Merge the strings by adding letters in alternating order, starting with word1
. If a string is longer than the other, append the additional letters onto the end of the merged string.
Return the merged string.
Example 1:
Input: word1 = "abc", word2 = "pqr" Output: "apbqcr" Explanation: The merged string will be merged as so: word1: a b c word2: p q r merged: a p b q c r
Example 2:
Input: word1 = "ab", word2 = "pqrs" Output: "apbqrs" Explanation: Notice that as word2 is longer, "rs" is appended to the end. word1: a b word2: p q r s merged: a p b q r s
Example 3:
Input: word1 = "abcd", word2 = "pq" Output: "apbqcd" Explanation: Notice that as word1 is longer, "cd" is appended to the end. word1: a b c d word2: p q merged: a p b q c d
Constraints:
1 <= word1.length, word2.length <= 100
word1
andword2
consist of lowercase English letters.
Related Topics:
String
Similar Questions:
// OJ: https://leetcode.com/problems/merge-strings-alternately/
// Author: github.com/lzl124631x
// Time: O(M + N)
// Space: O(1)
class Solution {
public:
string mergeAlternately(string a, string b) {
int i = 0, j = 0, M = a.size(), N = b.size();
string ans;
while (i < M || j < N) {
if (i < M) ans += a[i++];
if (j < N) ans += b[j++];
}
return ans;
}
};