From 0108a6992c04f8e17fa4e8c5ce5395f977f41cb1 Mon Sep 17 00:00:00 2001
From: Priyanshuischamp <priyanshuchakraborty43@gmail.com>
Date: Sun, 6 Oct 2024 23:37:34 +0530
Subject: [PATCH] Create PaintersPartition.cpp

Added solution code for homework problem (painters partition problem) from your youtube video.
---
 .../PaintersPartition.cpp                     | 61 +++++++++++++++++++
 1 file changed, 61 insertions(+)
 create mode 100644 Lecture015 Binary Search Advanced Problems/PaintersPartition.cpp

diff --git a/Lecture015 Binary Search Advanced Problems/PaintersPartition.cpp b/Lecture015 Binary Search Advanced Problems/PaintersPartition.cpp
new file mode 100644
index 00000000..a6ebf362
--- /dev/null
+++ b/Lecture015 Binary Search Advanced Problems/PaintersPartition.cpp	
@@ -0,0 +1,61 @@
+#include <bits/stdc++.h>
+using namespace std;
+
+bool isPossible(vector<int> &boards, int n, int k, int mid) {
+    int painterCount = 1;
+    int boardcount = 0;
+
+    for(int i = 0; i < n; i++)
+    {
+        if(boardcount + boards[i] <= mid)
+        {
+            boardcount += boards[i];
+        }
+        else
+        {
+            painterCount++;
+            if(painterCount > k || boards[i] > mid)
+            {
+                return false;
+            }
+            boardcount = boards[i]; //ensures that when a new painter is assigned board, they start with the count of the current board (boards[i]).
+        }
+    }
+    return true;
+}
+
+int findLargestMinDistance(vector<int> &boards, int k)
+{
+
+    // Initialize the binary search range
+    int s = 0;
+    int boardsum = 0;
+    int n= boards.size();
+    
+    for(int i = 0; i < n; i++)
+    {
+        boardsum += boards[i];  // Total boardsum of all board
+    }
+    
+    int e = boardsum;  // End point: boardsum of all board
+    int ans = -1;
+    int mid = s + (e - s) / 2;
+    
+    // Binary search to find the minimum number of board
+    while(s <= e)
+    {
+        if(isPossible(boards, n, k, mid))
+        {
+            ans = mid;
+            e = mid - 1;  // Try for a smaller value
+        }
+        else
+        {
+            s = mid + 1;  // Try for a larger value
+        }
+        mid = s + (e - s) / 2;
+    }
+    
+    return ans;
+}
+