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Usage:
val va = Var(0) val vb = Var(0) val vc = Var(0) val zipped: Rx[(Int, Int, Int)] = va.zip(vb, vc)
zipped would change for a change in all inputs. See similar in MetaRx: https://github.com/MetaStack-pl/MetaRx/blob/d35ee24afaaa49ee044a1d991d2c096c7acbffed/shared/src/main/scala/pl/metastack/metarx/Channel.scala#L134
The text was updated successfully, but these errors were encountered:
zipWith could easily be implemented afterwards, like this: https://github.com/MetaStack-pl/MetaRx/blob/d35ee24afaaa49ee044a1d991d2c096c7acbffed/shared/src/main/scala/pl/metastack/metarx/Channel.scala#L145
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I've bumped into this and want it too
I'm doing this with Rx:
val va = Var(0) val vb = Var(0) val vc = Var(0) val zipped = Rx{ va(); vb(); vc() // more code }
Am I overlooking anything?
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Usage:
zipped would change for a change in all inputs. See similar in MetaRx: https://github.com/MetaStack-pl/MetaRx/blob/d35ee24afaaa49ee044a1d991d2c096c7acbffed/shared/src/main/scala/pl/metastack/metarx/Channel.scala#L134
The text was updated successfully, but these errors were encountered: