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rdd.filter() does not preserve partitioning? #17

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rtkaleta opened this issue Sep 26, 2017 · 0 comments
Open

rdd.filter() does not preserve partitioning? #17

rtkaleta opened this issue Sep 26, 2017 · 0 comments

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@rtkaleta
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Hi, thanks for writing the notebooks.

In the introduction to RDD partitioning you mention that the filter operation does not preserve partitioning. But I'm looking at the source code where I see that MapPartitionsRDD is instantiated with preservesPartitioning = true.

Doesn't this conflict your statement?
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