diff --git a/chapters/en/chapter5/evaluation.mdx b/chapters/en/chapter5/evaluation.mdx
index dfd8583c..3db97b94 100644
--- a/chapters/en/chapter5/evaluation.mdx
+++ b/chapters/en/chapter5/evaluation.mdx
@@ -36,12 +36,12 @@ insertions and deletions on the *word level*. This means errors are annotated on
 | Reference:  | the | cat | sat     | on  | the | mat |
 |-------------|-----|-----|---------|-----|-----|-----|
 | Prediction: | the | cat | **sit** | on  | the |     |  |
-| Label:      | ✅   | ✅   | S       | ✅   | ✅   | D   |
+| Label:      | ✅   | ✅   | S       | ✅   | ✅   | I   |
 
 Here, we have:
 * 1 substitution ("sit" instead of "sat")
-* 0 insertions
-* 1 deletion ("mat" is missing)
+* 1 insertions ("mat" is missing)
+* 0 deletion 
 
 This gives 2 errors in total. To get our error rate, we divide the number of errors by the total number of words in our
 reference (N), which for this example is 6:
@@ -49,7 +49,7 @@ reference (N), which for this example is 6:
 $$
 \begin{aligned}
 WER &= \frac{S + I + D}{N} \\
-&= \frac{1 + 0 + 1}{6} \\
+&= \frac{1 + 1 + 0}{6} \\
 &= 0.333
 \end{aligned}
 $$
@@ -116,17 +116,17 @@ individual characters, and annotate errors on a character-by-character basis:
 | Reference:  | t   | h   | e   |     | c   | a   | t   |     | s   | a     | t   |     | o   | n   |     | t   | h   | e   |     | m   | a   | t   |
 |-------------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-------|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|-----|
 | Prediction: | t   | h   | e   |     | c   | a   | t   |     | s   | **i** | t   |     | o   | n   |     | t   | h   | e   |     |     |     |     |
-| Label:      | ✅   | ✅   | ✅   |     | ✅   | ✅   | ✅   |     | ✅   | S     | ✅   |     | ✅   | ✅   |     | ✅   | ✅   | ✅   |     | D   | D   | D   |
+| Label:      | ✅   | ✅   | ✅   |     | ✅   | ✅   | ✅   |     | ✅   | S     | ✅   |     | ✅   | ✅   |     | ✅   | ✅   | ✅   |     | I  | I   | I   |
 
 We can see now that for the word "sit", the "s" and "t" are marked as correct. It's only the "i" which is labelled as a
 substitution error (S). Thus, we reward our system for the partially correct prediction 🤝
 
-In our example, we have 1 character substitution, 0 insertions, and 3 deletions. In total, we have 14 characters. So, our CER is:
+In our example, we have 1 character substitution, 3 insertions, and 0 deletions. In total, we have 14 characters. So, our CER is:
 
 $$
 \begin{aligned}
 CER &= \frac{S + I + D}{N} \\
-&= \frac{1 + 0 + 3}{14} \\
+&= \frac{1 + 3 + 0}{14} \\
 &= 0.286
 \end{aligned}
 $$