The pair sum of a pair (a,b) is equal to a + b. The maximum pair sum is the largest pair sum in a list of pairs.
- For example, if we have pairs
(1,5),(2,3), and(4,4), the maximum pair sum would bemax(1+5, 2+3, 4+4) = max(6, 5, 8) = 8.
Given an array nums of even length n, pair up the elements of nums into n / 2 pairs such that:
- Each element of
numsis in exactly one pair, and - The maximum pair sum is minimized.
Return the minimized maximum pair sum after optimally pairing up the elements.
Example 1:
Input: nums = [3,5,2,3] Output: 7 Explanation: The elements can be paired up into pairs (3,3) and (5,2). The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7.
Example 2:
Input: nums = [3,5,4,2,4,6] Output: 8 Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2). The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8.
Constraints:
n == nums.length2 <= n <= 105nis even.1 <= nums[i] <= 105
Companies:
eBay
// OJ: https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/
// Author: github.com/lzl124631x
// Time: O(NlogN)
// Space: O(1)
class Solution {
public:
int minPairSum(vector<int>& A) {
sort(begin(A), end(A));
int ans = 0;
for (int i = 0; i < A.size() / 2; ++i) {
ans = max(ans, A[i] + A[A.size() - 1 - i]);
}
return ans;
}
};