Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has a size equal to m + n such that it has enough space to hold additional elements from nums2.
Example 1:
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Example 2:
Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
Constraints:
- nums1.length == m + n
- nums2.length == n
- 0 <= m, n <= 200
- 1 <= m + n <= 200
- -109 <= nums1[i], nums2[i] <= 109
Follow up: Can you come up with an algorithm that runs in O(m + n) time?
class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m-1;
int j = n-1;
int k = m+n-1;
while(i>=0||j>=0){
if(i<0){
nums1[k--] = nums2[j--];
}else if(j<0){
nums1[k--] = nums1[i--];
}else if(nums1[i]<nums2[j]){
nums1[k--] = nums2[j--];
}else{
nums1[k--] = nums1[i--];
}
}
}
}