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No, it is still a VAE since the MLPs will provide in this case the parameters of the distributions. Mean and covariance of the posterior q(z|x) are given by the encoder while the mean of p(x|z) is given by the decoder. |
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So we still have q(z | x) and p(x | z) are each Gaussians even if encoder = decoder = none? |
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Great thanks! |
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If I run a RHVAE with encoder = decoder = none, it seems from the documentation that encoder = decoder = MLP. In this case, is it true that this is just an autoencoder (and not a VAE) because there is no distribution?
Thanks!
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