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chap1q56_63.tex
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chap1q56_63.tex
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\documentclass[fleqn]{exam}
\usepackage{chemfig}
\usepackage{siunitx}
\begin{document}
\begin{questions}
\setcounter{question}{55}
\question In the following reaction mechanisms identify
(i) the catalyst
(ii) the reaction intermediate(s)
(iii) the overall reaction
\begin{parts}
\part
\schemestart
\chemfig{CH_2 = CH_2 + H^+} \arrow{->} \chemfig{CH_3 - CH_2^+}
\schemestop
\newline
\schemestart
\chemfig{CH_3 - CH_2^+ + H_2O} \arrow{->} \chemfig{CH_3 - CH_2 - OH + H^+}
\schemestop
\vspace{0.5in}
\part
A + B $\rightarrow$ C
\newline
C + D $\rightarrow$ E + F
\newline
E + B $\rightarrow$ D + F
\vspace{0.5in}
\part
\schemestart
\chemfig{NH_2NO_2 + CH_3COO^{-}} \arrow{->} \chemfig{CH_3COOH + NHNO_2^{-}}
\schemestop
\newline
\schemestart
\chemfig{NHNO_2^{-}} \arrow{->} \chemfig{N_2O+OH^{-}}
\schemestop
\newline
\schemestart
\chemfig{OH^{-} + CH_3COOH} \arrow{->} \chemfig{H_2O + CH_3COO^{-}}
\schemestop
\vspace{0.5in}
\part
\schemestart
\chemfig{Pt + C_2H_2} \arrow{->} \chemfig{PtC_2H_2}
\schemestop
\newline
\schemestart
\chemfig{PtC_2H_2 + H_2} \arrow{->} \chemfig{PtC_2H_4}
\schemestop
\newline
\schemestart
\chemfig{PtC_2H_4 + H_2} \arrow{->} \chemfig{Pt + C_2H_6}
\schemestop
\vspace{0.5in}
\part A $\rightarrow$ 2B
\newline
B + C $\rightarrow$ D + E
\newline
D + F $\rightarrow$ C + G
\newline
B + G $\rightarrow$ H
\vspace{0.5in}
\end{parts}
\question ``All catalyzed reaction mechanisms have more than one step.'' Why must this statement be true?
\vspace{1in}
\question Suppose a catalyzed reaction is occurring in a reaction container. If the catalyst is removed, will the reaction stop completely? Explain your answer.
\vspace{1in}
\question Can a catalyst cause an exothermic reaction to become endothermic, or vice versa? Explain.
\vspace{1in}
\question Consider the following reaction mechanism: X+Y$\rightarrow$ Z (very fast) \newline
Z + Y $\rightarrow$ P (very fast) \newline
P + Y $\rightarrow$ Q (slow) \newline
Suppose there was a catalyst that worked on step 1, and another catalyst that worked on step 3.
Which catalyst would be ineffective in increasing the rate of the overall reaction?
\vspace{1in}
\question If you have a slow reaction and add a substance that provides an alternate reaction mechanism having a higher activation energy, what will happen to the reaction rate? Why does this occur?
\vspace{1in}
\question Chlorine atoms are present in the upper atmosphere as a result of emissions from volcanoes and man-made pollutants. The reaction between chlorine atoms and ozone is thought to proceed by a 2-step mechanism:
\schemestart
\chemfig{O_3 + Cl} \arrow{->} \chemfig{ClO + O_2}
\schemestop
\newline
\schemestart
\chemfig{O + ClO} \arrow{->} \chemfig{O_2 + Cl}
\schemestop
\newline
\begin{parts}
\part What is the overall reaction?
\vspace{1in}
\part Identify any reaction intermediates or catalysts present.
\vspace{1in}
\part Suggest a reason why chlorine atoms in the upper atmosphere are a threat to the environment.
\vspace{1in}
\part Why does the presence of chlorine atoms in the upper atmosphere allow more UV light to reach the earth's surface? \[Hint: look at reaction (3) on the previous page.\]
\end{parts}
\newpage
\question The catalyzed reaction between \chemfig{CH_3OH} (an alcohol) and \chemfig{CH_3COOH} (an organic acid) to make \chemfig{CH_3COOCH_3} (an ester) proceeds as follows.
\newline
\schemestart
\chemfig{CH_3OH + H^+} \arrow{->} \chemfig{CH_3OH_2^2}
\schemestop
\newline
\schemestart
\chemfig{CH_3OH_2^2} \arrow{->} \chemfig{CH_3^+ + H_2O}
\schemestop
\newline
\schemestart
\chemfig{CH_3^+ + CH_3COOH} \arrow{->} \chemfig{CH_3COOHCH_3^+}
\schemestop
\newline
\schemestart
\chemfig{CH_3COOHCH_3^+} \arrow{->} \chemfig{CH_3COOCH_3 + H^+}
\schemestop
\newline
\begin{parts}
\part What is the overall reaction?
\vspace{1in}
\part Why is the reaction said to be "acid catalyzed"?
\vspace{1in}
\part If the \chemfig{H^+} used in the first step was radioactive, Would the \chemfig{CH_3COOCH_3} produced in the 4th step contain a radioactive hydrogen atom? Why?
\end{parts}
\end{questions}
\end{document}