How to get parsed data ( key -> value) of Class Decorator

[knlodha]

Hi @buehler ,
I can see that, I am not getting parsed data for class decorator. How can I get this data provided in decorator. I am using it for angular files

e.g.
import { Component } from '@angular/core';

@component({
selector: 'app-root',
template: <h1>{{title}}</h1> <h2>My favorite hero is: {{myHero}}</h2>
})
export class AppComponent {
title = 'Tour of Heroes';
myHero = 'Windstorm';
}

Here , I need selector and template values from decorator. Is there any way / configuration to get this data using parseSource or parseFile ?

[buehler]

Hey @knlodha
Right now, there is no possibility to get decorators (or preciser input values that are given into a decorator).

What you could do: search for the classes (and therefore the files) that have components in them and then use a string search to parse those elements.

[knlodha]

Hi @buehler ,
Thanks a lot for the inputs. Currently, I am doing exactly what you suggested ( string parsing ).
However, in certain scenarios like below,

Angular Code:
const routes: Routes = [
{ path: '', redirectTo: '/dashboard', pathMatch: 'full' },
{ path: 'dashboard', component: DashboardComponent },
{ path: 'detail/:id', component: HeroDetailComponent },
{ path: 'heroes', component: HeroesComponent }
];

where I need individual objects like the one highlighted above, string parsing becomes more complex.
Also, I can not covert the parsed string into Javascript object using JSON.parse as it will not find the individual references like DashboardComponent in this case.

Why I can't get the values of variables like routes using typescript parser. I can see, I only get the datatype. Is there any other way to get such information.

Also, do we have something like esprima ( http://esprima.org/ )for typescript code.