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I2C SDA and SDC pins are hardcoded to use VDDIO as vssel #1047

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@JordanAceto

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@JordanAceto

Hi there,

I am working with the MAX32666 on a FTHR2 board. I configured I2C2 as a master like this (simplified for clarity):

MXC_I2C_Init(MXC_I2C2_BUS0, I2C_CFG_MASTER_MODE, 0);
MXC_I2C_SetFrequency(MXC_I2C2_BUS0, MXC_I2C_STD_MODE);

... and tied the 10k pullups to 3.3v using jumper J4 on the FTHR2.

With an oscilloscope I found that the SDA and SCL lines had a maximum of around 2.2v, not the expected 3.3v.

Running through the debugger I found that during the MXC_I2C_Init() call in i2c_me14.c a mxc_gpio_cfg_t is used to configure the SDA and SCL pins. This is hardcoded to use VDDIO as the .vssel field.

The init call is here:

MXC_GPIO_Config(&gpio_cfg_i2c2);

And the definition of the mxc_gpio_cfg_t struct is here:

const mxc_gpio_cfg_t gpio_cfg_i2c2 = { MXC_GPIO1, (MXC_GPIO_PIN_14 | MXC_GPIO_PIN_15), MXC_GPIO_FUNC_ALT1,
MXC_GPIO_PAD_NONE, MXC_GPIO_VSSEL_VDDIO, MXC_GPIO_DRVSTR_0 };

In my main function I added this code to re-initialize the SDA and SCL pins to use VDDIOH after the MXC_I2C_Init() call, and this does now bring the high level of both lines to 3.3v:

	const mxc_gpio_cfg_t i2c2_sda_pin = {
		.port = MXC_GPIO1,
		.mask = MXC_GPIO_PIN_15,
		.pad = MXC_GPIO_PAD_NONE,
		.func = MXC_GPIO_FUNC_ALT1,
		.vssel = MXC_GPIO_VSSEL_VDDIOH,
		.drvstr = MXC_GPIO_DRVSTR_0,
	};
	MXC_GPIO_Config(&i2c2_sda_pin);

	const mxc_gpio_cfg_t i2c2_scl_pin = {
		.port = MXC_GPIO1,
		.mask = MXC_GPIO_PIN_14,
		.pad = MXC_GPIO_PAD_NONE,
		.func = MXC_GPIO_FUNC_ALT1,
		.vssel = MXC_GPIO_VSSEL_VDDIOH,
		.drvstr = MXC_GPIO_DRVSTR_0,
	};
	MXC_GPIO_Config(&i2c2_scl_pin);

Question: Is this the intended way to use an I2C bus with 3.3v pullups? Is there some more ergonomic config I could do? It seems easy to miss this and then wonder why your pullups aren't pulling all the way to 3.3v. I'm definitely operating under the assumption that I might have missed something here, but if not there might be an opportunity for a slightly cleaner I2C config.

Thanks!

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