n-th_power.md

N-th Power

Description

This kata is from check py.checkio.org

You are given an array with positive numbers and a non-negative number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.

Let's look at a few examples:

• array = [1, 2, 3, 4] and N = 2, then the result is 3^2 == 9;
• array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.

My Solution

def index(array, n)
  array[n] ? array[n] **n : -1
end

Better/Alternative solution from Codewars

def index(arr, n)
  arr[n] ** n rescue -1
end