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find_nearest_square_number.md

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Description

Your task is to find the nearest square number, nearest_sq(n) or nearestSq(n), of a positive integer n.

For example, if n = 111, then nearest\_sq(n) (nearestSq(n)) equals 121, since 111 is closer to 121, the square of 11, than 100, the square of 10.

If the n is already the perfect square (e.g. n = 144, n = 81, etc.), you need to just return n.

Good luck :)

My Solution

def nearest_sq(n)
  Math.sqrt(n).round ** 2
end