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84. Largest Rectangle in Histogram
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84. Largest Rectangle in Histogram
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//here we have to learn two more quentions first ...
//Which are most important in Stack
// 1.next Smaller Element
//2. prev Smaller Element
//then we will be able to solve it
//Formula----
// area = length * width;
class Solution {
public:
vector<int>nextSmallerElement(vector<int>& input){
stack<int>s;
s.push(-1);
vector<int>ans(input.size());
for(int i=input.size()-1;i>=0;i--){
int curr = input[i];
while(s.top()!= -1 && input[s.top()] >= curr){
s.pop();
}
//chota mil chuka hai store ans
ans[i] = s.top();
//push kardo element ko
s.push(i);
}
return ans;
}
vector<int>prevSmallerElement(vector<int>& input){
stack<int>s;
s.push(-1);
vector<int>ans(input.size());
//left to right
for(int i=0;i<input.size();i++){
int curr = input[i];
while(s.top()!= -1 && input[s.top()] >= curr){
s.pop();
}
//chota element mil chuka hai
ans[i] = s.top();
//push kardo elment ko
s.push(i);
}
return ans;
}
int largestRectangleArea(vector<int>& heights) {
//prev smaller call
vector<int>prev = prevSmallerElement(heights);
//next smaller call
vector<int>next = nextSmallerElement(heights);
int MaxArea = INT_MIN;
int size = heights.size();
for(int i=0;i<heights.size();i++){
int length = heights[i];
if(next[i] == -1){
next[i] = size;
}
int width = next[i] - prev[i] -1;
int area = length * width;
MaxArea = max(MaxArea,area);
}
return MaxArea;
}
};