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Skipped
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Car moves 50m in 5s a.
$\displaystyle v = \frac{m}{s} = \frac{50}{2} = 10\frac{m}{s}$ b. c. Bei der Hälfte -
Sportscar accelerates in 3rd gear from
$48.3 km/h$ to$80.5 km/h$ within$3.7s$ - How big is his average acceleration?
$\delta v = v_E - v_A = 80.5km/h - 48.3km/h = 32.2km/h$ $a = \frac{v_E - v_A}{t} = \frac{(80.5km/h - 48.3km/h)/3.6}{3.7s} = \underline{\underline{2.42m/s}}$
- How fast would it be, if it accelerated at that pace for an hour?
$1h = 3600s$ $80.5km/h / 3.6 = 22.36m/s$ $\displaystyle v_E = v_A + a_m * t = 22.36m/s + 2.42m/s * 3600s = \underline{\underline{8725 m/s}}$
- How big is his average acceleration?
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Car starts from standing. Endspeed is
$30m/s$ , drives for$10s$ .- How far did it drive?
$\overline{v} = v_E / 2 = 30m/s / 2 = 15m/s$ $s_Auto = \overline{v} * t = 15m/s * 10s = \underline{\underline{150m}}$
- How far did it drive?
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Car starts from standing. Constant acceleration of
$1m/s^2$ .- Which distance
$s$ did the car cover, if it's end velocity$v_E$ is$5 m/s$
$\displaystyle s=\frac{v_E^2-v_A^2}{2a}=\frac{5^2m/s}{2m/s^2}=\frac{25m/s}{2m/s^2}=\underline{\underline{12.5m}}$
- Which distance
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Car starts from standing. Starts
$10m$ behind the origin and reaches$60m$ in$10s$ - What is it's average speed?
$\overline{v} = s / t = 60m / 10s = \underline{\underline{6 m/s}} $
- Which Position
$s$ does the Car have compared to the origin?$s_T = s - s_U = 60m - 10m = \underline{\underline{50m}}$
- What is it's average speed?
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What is the velocity
$v$ of a Car, that is already driving at$v_A=10m/s$ and accelerates at$0.1m/s^2$ for$10$ seconds?- What is it's endvelocity
$v_E$ ?$v_E=v_A+a*t=10m/s+0.1m/s^2*10=\underline{\underline{11m/s}}$
- What is it's endvelocity
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A car has a startvelocity
$v_A = 6m/s$ and travels$40m$ within the first$5s$ .- What is the acceleration?
$s = v_A*t + 0.5at^2$ $40 = 6*5 + 0.5a*(5^2)$ $40 = 30 + 0.5a*25$ $40 = 30 + 12.5a$ $10 = 12.5a$ $a = 0.8m/s^2$
- What is the acceleration?